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. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person selected at

Home/Math/. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person selected at

. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person selected at

Question

. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person selected at random will have an IQ of 110 or greater?

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

has a pvalue of 0.9772

1 – 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

## Answers ( )

Answer:2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:Problems of normally distributed samples are solved using the z-score formula.In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:What is the probability that a person selected at random will have an IQ of 110 or greater?This is 1 subtracted by the pvalue of Z when X = 110. So

has a pvalue of 0.9772

1 – 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater